Math, asked by joekr92928, 10 months ago

x+y=5xy
3x+2y=13xy
find x and y​

Answers

Answered by rohin111bhattacharya
12

Answer:

X=4

Y=8

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Answered by varadad25
4

Answer:

The solution of the given simultaneous equations is

\boxed{\red{\sf\:x\:=\:\dfrac{1}{2}}}\sf\:\:\&\:\:\boxed{\red{\sf\:y\:=\:\dfrac{1}{3}}}

Step-by-step-explanation:

The given simultaneous equations are

\sf\:x\:+\:y\:=\:5xy\:\:\:\:-\:-\:(\:1\:)\\\\\sf\:3x\:+\:2y\:=\:13xy\:\:\:-\:-\:(\:2\:)

Now, by multiplying equation ( 1 ) by 2, we get,

\sf\:2x\:+\:2y\:=\:10xy\:\:\:-\:-\:(\:3\:)

By subtracting equation ( 3 ) from equation ( 2 ), we get,

\sf\:3x\:+\:\cancel{2y}\:=\:13xy\:\:\:-\:-\:(\:2\:)\\\sf\:-\\\underline{\sf\:2x\:+\:\cancel{2y}\:=\:10xy}\sf\:\:\:-\:-\:(\:3\:)\\\\\\\implies\sf\:x\:=\:3xy\\\\\\\implies\sf\:\dfrac{\cancel{x}}{\cancel{x}y}\:=\:3\\\\\\\implies\sf\:\frac{1}{y}\:=\:3\\\\\\\implies\boxed{\red{\sf\:y\:=\:\frac{1}{3}}}

By substituting \sf\:y\:=\:\dfrac{1}{3} in equation ( 1 ), we get,

\sf\:x\:+\:y\:=\:5xy\:\:-\:-\:-\:(\:1\:)\\\\\\\implies\sf\:x\:+\:\frac{1}{3}\:=\:5x\:\times\:\frac{1}{3}\\\\\\\implies\sf\:x\:+\:\frac{1}{3}\:=\:\frac{5x}{3}\\\\\\\implies\sf\:3x\:+\:1\:=\:5x\:\:\:-\:-\:[\:Multiplying\:by\:3\:]\\\\\\\implies\sf\:5x\:-\:3x\:=\:1\\\\\\\implies\sf\:2x\:=\:1\\\\\\\implies\boxed{\red{\sf\:x\:=\:\frac{1}{2}}}

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Additional Information:

1. Linear Equations in two variables:

The equation with the highest index (degree) 1 is called as linear equation. If the equation has two different variables, it is called as 'linear equation in two variables'.

The general formula of linear equation in two variables is

ax + by + c = 0

Where, a, b, c are real numbers and

a ≠ 0, b ≠ 0.

2. Solution of a Linear Equation:

The value of the given variable in the given linear equation is called the solution of the linear equation.

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