Math, asked by naveenraja4832, 17 days ago

x*(y+(-6))=(13*(-19)+(13*z)​

Answers

Answered by pulakmath007
1

The values are x = 13 , y = - 19 , z = - 6

Correct question : Find the value of x ,y,z from the following x × [y + (-6)] = [13 × (-19)] + [13 × z]

Given :

\displaystyle \sf{x \: \times \: [y + ( - 6)] =[13 \times ( - 19)] +[13 \times z] }

To find :

The value of x , y , z

Concept :

Distributive Property :

For three real numbers a , b , c

 \sf{a \times (b + c) = (a \times b) + (a \times c)}

Solution :

Step 1 of 2 :

Write down the given expression

The given expression is

\displaystyle \sf{x \: \times \: [y + ( - 6)] =[13 \times ( - 19)] +[13 \times z] }

Step 2 of 2 :

Find the value of x , y , z

We apply the Distributive Property

 \sf{a \times (b + c) = (a \times b) + (a \times c)}

Thus we get

\displaystyle \sf{x \: \times \: [y + ( - 6)] =[13 \times ( - 19)] +[13 \times z] }

\displaystyle \sf\implies x \: \times \: [y + ( - 6)] =13 \times [( - 19) + z]

Comparing both sides we get x = 13 , y = - 19 , z = - 6

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