Math, asked by rahul9385, 1 year ago

x+y=6 and x-y=4 find x^2+y^2

Answers

Answered by Anonymous
20

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 \huge  \bf \sf{It \:  is \:  given  \: that:-)}


→ x + y = 6..............(1).

→ x - y = 4................(2).


➡ Add in equation (1) and (2).


x + y = 6.
x - y = 4.
(+)..(-)....(+)
________
=> 2x = 10.

=> x =  \frac{10}{2} .


 \huge \boxed{=> x = 5.}



➡ Put the value of ‘x’ in equation (1).


=> 5 + y = 6.

=> y = 6 - 5.

 \huge \boxed{=> y = 1.}


▶ Now, A/Q.


 \huge \bf =  {x}^{2}  +  {y}^{2} .



 \bf =  {(5)}^{2}  +  {(1)}^{2} .


 \bf = 25 + 1.


 \huge \boxed{ = 26.}


✔✔ Hence, it is founded ✅✅.

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 \huge \bf{ \# \mathbb{B}e \mathbb{B}rainly.}

Anonymous: kp it ^
Answered by vikram991
5
here is your answer OK


Given,

x + y= 6 (equation 1)

x - y = 4 (equation 2)

Squaring and adding both the equations,

(x + y)² + (x - y)² = 6² + 4²

=> x² + y² + 2xy + x² + y² - 2xy = 52

=> 2(x²+y²) = 52

=> x²+y²=26
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