x+y=6 and x-y=4 find x^2+y^2
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Answered by
20
→ x + y = 6..............(1).
→ x - y = 4................(2).
➡ Add in equation (1) and (2).
x + y = 6.
x - y = 4.
(+)..(-)....(+)
________
=> 2x = 10.
➡ Put the value of ‘x’ in equation (1).
=> 5 + y = 6.
=> y = 6 - 5.
▶ Now, A/Q.
✔✔ Hence, it is founded ✅✅.
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Anonymous:
kp it ^
Answered by
5
here is your answer OK
Given,
x + y= 6 (equation 1)
x - y = 4 (equation 2)
Squaring and adding both the equations,
(x + y)² + (x - y)² = 6² + 4²
=> x² + y² + 2xy + x² + y² - 2xy = 52
=> 2(x²+y²) = 52
=> x²+y²=26
Given,
x + y= 6 (equation 1)
x - y = 4 (equation 2)
Squaring and adding both the equations,
(x + y)² + (x - y)² = 6² + 4²
=> x² + y² + 2xy + x² + y² - 2xy = 52
=> 2(x²+y²) = 52
=> x²+y²=26
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