X+y=6 and xy=8then find x3 + y3
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Answer:
x³ + y³ = 62
step-by-step explanation:
Given:
x + y = 6 and xy = 8
To find:
x³ + y³
Solution:
Since, x + y = 6
=> (x + y)³ = 6³ [cubing on both
the sides]
=> x³+ y³+3xy (x + y)= 216 [(a+b)³=a³+b³+3ab(a+b)]
=> x³ + y³ + 3(8)(6)= 216 [given; x+y=6 & xy=8]
=> x³ + y³ + 144= 216
=> x³ + y³ = 216 - 144
=> x³ + y³ = 62
Answer..
Hope this helped you...
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