Question

x-y=-6, xy=4, x^3-y^3=?

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

x^3 - y^3 = (x-y) [(x-y)^2 + 3xy]

= -6 (36 +12)

= -288

Therefore,

x^3-y^3= -288

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