Question

x+y=7/2, xy=5/2, find x-y qnd x²-y²​

Answer 1

Step-by-step explanation:

(x-y)²= x²+ y²-2xy

(x-y) ² = (7/2)² - 2(5/2)

(x-y)²= 49/4 - 10/2

(x-y)²= 49/4 - 20/4

(x-y)²= 29/4

$x - y = \sqrt{ \frac{29}{4} }$

(x-y) ² = x²+y²-2xy

(x-y)²= 49/4- 20/4

(x-y)²= 29/4

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Answer 2

Answer:

formula: (x-y)^2 = (X+y)^2 - 4xy

= (7/2)^2-4(5/2)

=49/4 - 10

=9/4

x-y= √9/4

x-y= 3/2,-3/2

(x^2-y^2)

formula: (x-y)(x+y)

(3/2)(7/2)

=(21/4)

we take -3/2

(-3/2)(7/2)

=(-21/4)

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