Question

x+y=7 2x+3y=15 by elimination method​

Answer 1

$\huge \sf{\underline{ Question:}}$

$\sf{solve \: \: x+y=7 \: \: and \: \: 2x+3y=15 \: \: by \: \: elimination \: \: method.}$

$\huge \sf\red{\underline{ \underline{Answer :}}}$

$\boxed{ \large{ \bf{x = 6 \: \: \: \: y = 1}}}$

▪︎See the attachment for steps .

Answer 2

Answer:

2x+3y=15 ----- (1)

3x+3y=12 ----- (2)

(-) (-) (-)

_____________

−x=3

x=−3

Put the value of x in equation (1), we get

2x+3y=15

2(−3)+3y=15

−6+3y=15

3y=15+6

3y=21

y=

3

21

y=7

Therefore the solution is (−3,7)