x/y=7/4 find the value of x3-y3/y3
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Given X = 7 and Y = 4
===> X3 - Y3 / Y3
===> ( 7 ) 3 - ( 4) 3 / ( 4 ) 3
===> 343 - 48 / 48
===> 295 / 48
===> 6.145833333.........
Answered by
0
Answer:
Given x = 7
y = 4
so, x3-y3/y3
=7(3)-4(3)/4(3)
=21-12/12
=21-1
=20.
If given in powers
then,7^3-4^3/4^3
=343-4^0 {a^m/a^n=a^m-n}
=343-1 {a^0=1}
=342
Hope u got ur answer.
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