Math, asked by Mesha5971, 1 year ago

x/y=7/4 find the value of x3-y3/y3

Answers

Answered by LilyWhite
0

Given X = 7 and Y = 4

===> X3 - Y3 / Y3

===> ( 7 ) 3 - ( 4) 3 / ( 4 ) 3

===> 343 - 48 / 48

===> 295 / 48

===> 6.145833333.........

Answered by saic2160
0

Answer:

Given x =  7

y = 4

so, x3-y3/y3

=7(3)-4(3)/4(3)

=21-12/12

=21-1

=20.

If given in powers

then,7^3-4^3/4^3

=343-4^0           {a^m/a^n=a^m-n}

=343-1                {a^0=1}

=342

Hope u got ur answer.

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