x+y=7&2x-3y=11
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Answer:
x+y=7___(i)
2x-3y=11_(ii)
Using elimination method,
x+y=7__(i)×2
2x-3y=11__(ii)×1
_____________
2x+2y=14
2x-3y=11
- + -
_______
y=3
Putting y= 3 in eqⁿ(i),
x+y=7
x+3=7
x=7-3
x=4.
Hence the value of x= 4 AND y = 3.
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