Math, asked by masternavneet143, 1 year ago

x+y=7 and x-y=3, x2-y2=

Answers

Answered by Anonymous
2
X^2 - Y^2 =(X+Y) (X-Y) =7*3=21

HOPE IT HELPS YA

Pavansabani: x=5andy= 2 therefore x2 -y2= 21
Answered by rizwan35
0

given \: that \:  \\  \\ x + y = 7.....(1) \\  \\ and \:  \\ x - y = 3......(2) \\  \\ from \: equation \: (1) \\  \\ x + y = 7 \\  \\  =  > x = 7 - y \\  \\ putting \: this \: value \: of \: x \: in \: equation \: (2) \\  \\ 7 - y - y = 3 \\  \\  =  >  - 2y = 3 - 7 \\  \\  =  >  - 2y =  - 4 \\  \\  =  > y =  \frac{ - 4}{ - 2}  \\  \\  =  > y = 2 \\  \\ putting \: this \: value \: of \: y \: in \: equation \: (1) \\  \\ x + 2 = 7 \\  \\  =  > x = 7 - 2 \\  \\  =  > x = 5 \\  \\ therefore \\  \\ x = 5 \:  \: and \: y = 2 \\  \\ therefore \\  \\ x {}^{2}  - y {}^{2}  \\  \\  = 5 {}^{2}  - 2 {}^{2}  \\  \\  = 25 - 4 \\  \\  = 21 \\  \\  \\ hope \: it \: helps.....
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