Question

x+√y=7. Eq.1
√x+y=11. Eq.2
Find the value of x and y

Answer 1

$\sf \pmb{Answer :}$

=>x + √y = 7 and √x + y = 11

Consider

=>√x + y = 11

=>√x  = 11 - y

 =>Squaring on both sides

=>x = 121 - 22y + y2 

=>Put x = 121 - 22y + y2 in the equation x + √y = 7

=>Let √y = z

=>we get 121 + z4 - 22z2 + z = 7

=>We get factors z = ± 1, ± 2, ± 3, ± 6, ± 19, ± 57, ± 114 z = 3 satisfies the equation.

=>Now find the value of x and y we get x = 4 and y = 9

Answer 2

Answer:

value of x is 4 and value of y is 9.

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