Math, asked by aliya90, 1 year ago

x+y=7,x-y =1 solve the question graphically​

Answers

Answered by Flaunt
22

\sf\huge\bold{\underline{\underline{{Solution}}}}

We have given two pair of linear equations and we have to find the value of x and y through graph.

For that firstly convert the Equation either in the form of x or y and then plot points into and obtained the coordinate . Put the coordinate into graph of both the Equation and we obtained a interesting point with the help of coordinate of both the Equation which will be our final solution.

➙x+y= 7------(1)

➙x-y= 1-------(2)

Taking first Equation

x+y= 7

x=7-y

At y=0

➙x=7

At y=1

➙x= 6

we obtained the coordinate (7,0)&(6,1)

Now,plot the coordinates into graph

------------------------------------------------------------

Taking second Equation

x-y=1

x= y+1

At y=0

➙x=1

At y=1

➙x=2

Plot the coordinate (1,0)(2,1) into the graph

After plotting the coordinates of both the Equation we obtained a straight line graph which intersect at the points (4,3)

Hence,the solution of the given pair of linear equations is x= 4 & y= 3.

Check:

➙x+y=7

➙4+3=7

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Answered by ItzBrainlyBeast
45

\LARGE\textsf{\underline\textcolor{aqua}{↭ SoLuTioN :-}}

\large\textsf{                                                               }

\qquad\tt{:}\longrightarrow\large\textsf{x + y = 7}

\qquad\tt{:}\longrightarrow\large\textsf{x = 7 - y ----- ( i )}

\large\textsf{                                                               }

\qquad\tt{:}\longrightarrow\large\textsf{x - y = 1}

\qquad\tt{:}\longrightarrow\large\textsf{x = 1 + y ----- ( ii )}

\large\textsf{                                                               }

( i ) x = 7 - y

\boxed{\begin{array}{c | c | c | c }\bf{x} & \sf{2} & \sf{3} & \sf{4}\\ \bf{y} & \sf{5} & \sf{4} & \sf{3} \\ \bf{ ( x , y )} & \bf{( 2 , 5 )} & \bf{( 3 , 4 )} & \bf{( 4 , 3 )}\\ \end{array}}

\large\textsf{                                                               }

↦ When y = 5

↦ x = 7 - 5

x = 2

\large\textsf{                                                               }

↦ When y = 4

↦x = 7 - 4

x = 3

\large\textsf{                                                               }

↦ When y = 3

↦x = 7 - 3

x = 4

\large\textsf{                                                               }

Plot the obtained coordinates on the graph .

__________________________________________________________

( ii ) x = 1 + y

\boxed{\begin{array}{ c | c | c | c }\bf{x} & \sf{4} & \sf{3} & \sf{2} \\ \bf{y} & \sf{3} & \sf{2} & \sf{1} \\ \bf{ ( x , y )} & \bf{ ( 4 , 3 )} & \bf{ ( 3 , 2 ) } & \bf{ ( 2 , 1 )}\\ \end{array}}

\large\textsf{                                                               }

↦ When y = 3

↦x = 1 + 3

x = 4

\large\textsf{                                                               }

↦ When y = 2

↦x = 1 + 2

x = 3

\large\textsf{                                                               }

↦ When y = 1

↦x = 1 + 1

x = 2

\large\textsf{                                                               }

Plot the obtained coordinates on the graph .

\large\textsf{                                                               }

\large\textsf\textcolor{orange}{∴ The lines intersect at ( 4 , 3 )}

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