Question

X+√y=7 √x+y=11. find the value of x?

Answer 1

Answer:

x = 4, y = 9

Step-by-step explanation:

√y = 7 - x > 0 and √x = 11 - y > 0, therefore "x" can not be greater than 7 and "y" can not be greater than 11.

Assume the "x" and "y" are perfect squares between 1 and 11. Perfect squares are 1, 4, 9, 16, .... Thus, x = 4 and y = 9.

Check the answer:

1). 4 + √9 = 7

4 + 3 = 7

7 = 7

2). √4 + 9 = 11

2 + 9 = 11

11 = 11