Math, asked by RiyaVarda, 9 months ago

x+y =8
1/x +1/y = 8/15 find X and y​

Answers

Answered by dhareaveer
2

Answer:

Your answer is

Step-by-step explanation:

x + y = 8.

x = 8 - y.

Put this value in second equation.

1/x + 1/y = 8/15.

1/8-y + 1/y = 8/15.

8/8y-y^2 = 8/15.

15 = 8y - y^2.

y^2 -8y + 15 = 0.

y^2 - 5y - 3y + 15 = 0.

y( y - 5) -3 (y - 5) = 0

(y - 5)( y - 3 ) = 0 .

y = 5 , 3.

x = 8 - y.

x = 8-5 , 8-3.

x = 3 , 5.

Hope you understood my answer. If yes then plz mark me as the brainliest.

Answered by brainlygirl87
1

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{X+Y=8} …….…(1)

{X+Y=8} …….…(1)1/x +1/Y=8/15

{X+Y=8} …….…(1)1/x +1/Y=8/15X+Y/XY=8/15

{X+Y=8} …….…(1)1/x +1/Y=8/15X+Y/XY=8/158/XY=8/15

{X+Y=8} …….…(1)1/x +1/Y=8/15X+Y/XY=8/158/XY=8/15{XY=15}. ………..(2)

{X+Y=8} …….…(1)1/x +1/Y=8/15X+Y/XY=8/158/XY=8/15{XY=15}. ………..(2)Y=15/X (PUT IN ..1 )

{X+Y=8} …….…(1)1/x +1/Y=8/15X+Y/XY=8/158/XY=8/15{XY=15}. ………..(2)Y=15/X (PUT IN ..1 )X+ 15/X=8

{X+Y=8} …….…(1)1/x +1/Y=8/15X+Y/XY=8/158/XY=8/15{XY=15}. ………..(2)Y=15/X (PUT IN ..1 )X+ 15/X=8 X^2+15=8X

{X+Y=8} …….…(1)1/x +1/Y=8/15X+Y/XY=8/158/XY=8/15{XY=15}. ………..(2)Y=15/X (PUT IN ..1 )X+ 15/X=8 X^2+15=8XX^2–8X+15=0

{X+Y=8} …….…(1)1/x +1/Y=8/15X+Y/XY=8/158/XY=8/15{XY=15}. ………..(2)Y=15/X (PUT IN ..1 )X+ 15/X=8 X^2+15=8XX^2–8X+15=0(X–3)(X–5)=0

{X+Y=8} …….…(1)1/x +1/Y=8/15X+Y/XY=8/158/XY=8/15{XY=15}. ………..(2)Y=15/X (PUT IN ..1 )X+ 15/X=8 X^2+15=8XX^2–8X+15=0(X–3)(X–5)=0WHEN, X=3

{X+Y=8} …….…(1)1/x +1/Y=8/15X+Y/XY=8/158/XY=8/15{XY=15}. ………..(2)Y=15/X (PUT IN ..1 )X+ 15/X=8 X^2+15=8XX^2–8X+15=0(X–3)(X–5)=0WHEN, X=3Y=5

{X+Y=8} …….…(1)1/x +1/Y=8/15X+Y/XY=8/158/XY=8/15{XY=15}. ………..(2)Y=15/X (PUT IN ..1 )X+ 15/X=8 X^2+15=8XX^2–8X+15=0(X–3)(X–5)=0WHEN, X=3Y=5WHEN, X=5

{X+Y=8} …….…(1)1/x +1/Y=8/15X+Y/XY=8/158/XY=8/15{XY=15}. ………..(2)Y=15/X (PUT IN ..1 )X+ 15/X=8 X^2+15=8XX^2–8X+15=0(X–3)(X–5)=0WHEN, X=3Y=5WHEN, X=5Y=3.

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