Question

X+Y=8 and X-Y=6, What is the value of x^2+Y^2?

Answer 1

${\huge {\mathfrak {Answer :-}}}$

✨${} (x + y)^2 + (x - y)^2 = 2 (x^2 + y^2)$

${} \implies x^2 + y^2 = (8^2 + 6^2) / 2$

${} \implies x^2 + y^2 = (64 + 36)/2 = 50.$

Done.. ✔️

=_='

Answer 2

X+Y=8
X = 8 - Y .......(I)

X - Y = 6
(8 - Y) - Y = 6 ( by substituting (i) )
8 - 2Y = 6
2Y = 8-6
2Y = 2
Y = 1

X = 8 - 1
X = 7

X^2 + Y^2
(7)^2 + (1)^2

49 + 1 = 50

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