Question

x-y=8 and xy=12 then x3-y3​

Answer 1

Answer:

To solve tHis You have to Apply some identities which are...

1. x^3-y^3 = (x-y)(x^2 + y^2 + xy)

2.(x-y)^2 = x^2 y^2 -2xy as....

from 2 we get the value of Xsquare + Ysquare to put in 1.....which is 40 and now put these all the values in 1

ans we get..

Xcube - Ycube = 4×52=208