Question

x+y = 8 and xy = 3 3/4 find the value of x - y

Answer 1

Hope it helps you

Please mark me as the Brainliest

Answer 2

Answer:

7 is the required value of (x - y)

Step-by-step explanation:

Explanation:

Given in the question, x + y = 8 and  xy = $3\frac{3}{4}$.

And according to the question we need to find out the value of (x - y).

Step 1:

Let x + y = 8 ...........(i) and

xy = $3\frac{3}{4}$ ..........(ii)

On squaring both sides of (i) we get,

$(x + y)^2 = 8^2$

⇒$(x^2 + y^2 + 2xy)$ = 64

Put the value of xy from (ii)

⇒$x^2 + y^2 + 2 .\frac{15}{4}$ = 64

⇒$x^2 + y^2$ = 64 - $\frac{15}{2}$ = $\frac{113}{2}$

Step 2:

Now, $(x - y)^2$ = $x^2 + y^2 - 2xy$

From step 1 we put the value of xy and ($x^2 + y^2$)

⇒$(x - y)^2$ = $\frac{113}{2} -2. \frac{15}{4}$= $\frac{113}{2} - \frac{15}{2}$

⇒$(x - y)^2$ = $\frac{98}{2}$ = 49

⇒(x - y) = $\sqrt{49}$ = 7

Final answer:

Hence, 7 is the required value of (x - y).

#SPJ2