x+y =8,XY=15 then find the value of x^4 + x^2y^2 +y^4
Answers
Answered by
0
x^4+x^2×y^2+y^4
= x^4+y^4+(x^2×y^2)
= (x+y)^4 +(xy)^2
In the question given that x+y =8 and xy=15
then, 8^4+15^2
That is , 4096+225
=4321
I hope it would help you
Similar questions