Question

x+y-a=0 ax+by-b2=0 solve it with substitution method​

Answer 1

Answer:

x=1-ab+b^2/a-b

y=a-1+ab-b^2/a-b

Step-by-step explanation:

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Answer 2

The given question is x+y-a=0.---1

ax+by-b2=0.-----2

we have to solve it by substitution method.

x+y-a=0

x+y=a

y=a-x.-----3

sub y=a-x in 2 we get,

$ax + b(a - x) - {b}^{2} = 0 \\ ax + ba - bx - {b \\ }^{2} = 0\\ x(a - b) + b(a - b) = 0. \\ (a - b)(x + b) = 0$

x+b= 1/a-b.

$x = \frac{1}{a - b} - b \\ = \frac{1 - ab + {b}^{2} }{a - b}$

sub x value in 3

y

$y = a \: - \frac{1 - ab + {b}^{2} }{a - b} \\ {a}^{2} - ab - (1 - ab + {b}^{2} ) \div (a - b) \\ \frac{ {a }^{2} - ab - 1 + ab - {b}^{2} }{a - b}$

$y = \frac{{a}^{2} - 1 - {b}^{2}} { a - b}$

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