x-y=a+b, ax+by=a²-b² solve by cross multiplication method
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The is not clear broo.....
Step-by-step explanation:
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Step-by-step explanation:
PROOF:
Multiplying (a+b) with it's conjugate pair as (a-b),
x-y = (a+b)* (a-b)/(a-b)
(x-y)(a-b) = (a+b)(a-b)
ax-ay-bx+by = a^2-b^2
ax+by-(ay+bx) = a^2-b^2
NOW,
x-y = a+b
comparing the LHS and RHS, we get,
x = a
y = -b
Put these values,
ax+by-[a(-b)+b(a)] = a^2-b^2
ax+by-(-ab+ab) = a^2-b^2
ax+by-0 = a^2-b^2
ax+by = a^2-b^2
HOPE THIS WILL HELP YOU, THANK YOU.
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