Question

X, Y and Z are elements in the same short period. The oxide of X is a giant molecule, the oxide of Y is a simple molecule and the oxide of Z is ionic. The arrangement of the elements in order of increasing atomic number would be a) X, Y, Z b) X, Z, Y c) Z, X, Y d) Y, Z, X

Answer 1

Answer:

Z,X,Y

Explanation:

Oxides of the elements on the left side of the periodic table create basic solutions when dissolved because the oxygen reacts with H+ in the water, while the original element leaves OH− in its ionic state, resulting in a higher [OH−] than [H+].

Oxides of the elements on the right side of the periodic table create acidic solutions when dissolved because they react with OH−to create negatively charged polyatomic anions that are stable and remain in their ionic states instead of reacting with H+, resulting in a higher [H+] than [OH−].

Oxides of the elements in the middle of the periodic table create neutral solutions because they react equally with H+ and OH− in water, resulting in [OH−] being equal to [H+]

Based on above properties, we see that correct order is Z,X,Y

Answer 2

Given elements are arranged in order of increasing atomic number as Z < X < Y.

Explanation:

In short period of periodic table, silica is the name of element whose oxide is a giant molecule. Hence, symbol X is Si (silica). It is given that the oxide Z is ionic in nature which means that element prior to Si is aluminium (Al).

As the oxide of Y is a simple molecule so, this means that Y is phosphorous (P).

As the atomic number of silica is 14, aluminium is 13 and phosphorous is 15. Therefore, given elements are arranged in order of increasing atomic number as follows.

Z < X < Y

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