X, Y and Z are real numbers, such that (X+Y)(X+Y+Z) = 120, (Y+Z)(X+Y+Z) = 96 (Z+x)(X+Y+Z) = 72, what is the maximum value of | X+Y-Z|-Z?
Answers
Answered by
0
Answer:
29
Step-by-step explanation:
YZ=38
XZ=28
YZ/XZ=19/14
Hence Z=2
Similar questions