x , y and z are the three real no , if x < y and z<0 then ( x × z < y × z)
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plz complete your question with proper details about x y and z
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For any real numbers x, y, z, if one has x > y and y > z, then one necessarily has x > z. ... Multiplicative compatibility: If x,y,z are real numbers, and x > y and z > 0, then xz > yz.
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