Question

x,y and Z can do a piece of work in 15. 12 and 30 days, respectively. They started work together, but
ter 2 days. In what time will the remaining work be completed by X and Z?
​

Answer 1

Step-by-step explanation:

answer see in the above picture

Answer 2

Answers :

6⅓ days

Step-by-step explanation:

X can do the work in 15 days

therefore, X's 1 day's work = 1/15 parts

Y can do the work in 12 day

therefore, Y's 1 day's work = 1/12 parts

Z can do the work in 30 day

therefore, Z's 1 day's work = 1/30 parts

(X,Y and Z)'s together work in 1 day=1/15+1/12+1/30

= 4+5+2/60

= 11/60

X,Y and Z can do the work in 2 days = 2×11/60

= 22/60

Remaining work = 1-22/60

= 60-22/60

= 38/60

= 19/30

Remaining will be completed by X and Y

X and Z can do the work in 1 day= 1/15+1/30

= 2+1/30

= 3/30

= 1/10

since, 1/10×10 => 1

therefore, X and Z can do the work in 1 day=10days

X and Z can do the work in 19/30 work in = 19/30×10

=> 19/3

=> 6⅓ Days