Question

(x+y)dy+(x-y)dx=0 when y=1,x=1​

Answer 1

Answer:

(x+y)dy + (x-y)dx =0

Substitute the value of x = 1 and y = 1,

(1+1)d(1) + (1-1)d(1) = 0

2d + 0 = 0

2d = 0

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