Math, asked by jimmyanderson, 1 day ago

{x + y > 1
{2x + 3y < 7

Answers

Answered by mohammedanas5352
0

Answer:

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If 2x+3y=7 and x−y=1 are two normals of a parabola from a point then third normal may be

Hard

Solution

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Correct option is

A

x−3y+1=0

2x+3y=7

3y=−2x+7

y=−

3

2

x+

3

7

m

1

=

3

−2

x−y=1

−y=−x+1

y=x−1

m

2

=1

For any parabola

m

1

+m

2

+m

3

=0

3

−2

+1+m

3

=0

3

−2+3

+m

3

=0

3

1

+m

3

=0

m

3

=−

3

1

Now check for all option

(A) x−3y+1=0

−3y=−x−1

m=

3

1

(B) x−3y+1=5

m=

3

1

(C) m=

2

1

So, none of these may be third normal

Answered by duddumidhuna
0

Step-by-step explanation:

answer is 1 ...

a =1

b=1 and c=1

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