{x + y > 1
{2x + 3y < 7
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If 2x+3y=7 and x−y=1 are two normals of a parabola from a point then third normal may be
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Correct option is
A
x−3y+1=0
2x+3y=7
3y=−2x+7
y=−
3
2
x+
3
7
m
1
=
3
−2
x−y=1
−y=−x+1
y=x−1
m
2
=1
For any parabola
m
1
+m
2
+m
3
=0
3
−2
+1+m
3
=0
3
−2+3
+m
3
=0
3
1
+m
3
=0
m
3
=−
3
1
Now check for all option
(A) x−3y+1=0
−3y=−x−1
m=
3
1
(B) x−3y+1=5
m=
3
1
(C) m=
2
1
So, none of these may be third normal
Answered by
0
Step-by-step explanation:
answer is 1 ...
a =1
b=1 and c=1
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