Question

x- y if x+ y =8 and xy=18​

Answer 1

Step-by-step explanation:

$\implies$ $(x+y)^{2}=x^{2}+y^{2}+2xy$

$\implies$ $8^{2}=x^{2}+y^{2}+2(18)$

$\implies$ $64-36=x^{2}+y^{2}$

$\implies$ $x^{2}+y^{2}=28$

Now,

$\implies$ $(x-y)^{2}=x^{2}+y^{2}-2xy$

$\implies$ $(x-y)^{2}=28-2(18)$

$\implies$ $\boxed{x-y=\sqrt{-8}}$

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