Question

x-y is 2 and xy is 8 , then find the value of x^3-y^3​

Answer 1

Step-by-step explanation:

{x-y}^3 = x^3 - y^3 -3×8{2}

8 +48 = x^3-y^3

= 56

Answer 2

Step-by-step explanation:

x-y=2

cubing both sides

(x-y)³=2³

x³-3xy(x-y)-y³=8

x³-y³-3(8)(2)=8

x³-y³=8+48

x³-y³=56