Question

(x/y) ^n-1=(y/x)^n-3 . Find the value of n.
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Answer 1

Answer: n=2

Step by step explaination :

$(x/y) ^{n-1}=(y/x)^{n-3}\\let\\ y/x =k\\ then\\x/y = 1/k\\\\(1/k)^{n-1} =k^{n-3}\\1= k^{n-3+n-1}\\1=k^{2n-4}\\k^0=k^{2n-4}\\2n-4=0\\n=2$

Answer 2

Step-by-step explanation:

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