Question

x y nd z are the real number . if x<y nd z<o then​

Answer 1

We are given:

• x, y and z are three real numbers.
• x <y and z<0

If these options are given as answer:

(a) xxz < y z (b) xxz>yxz (c) xx zs yxz (d) xx z = yxz​

then: xxz < y z

z < 0

=> xx > y

=> x ² > y

if x = 2    y  =  8

Then 2² = 4 < 8 which is not valid in all conditions

xx z = yxz​

cancelling xz

=> x = y

but x < y

xxz>yxz

Dividing both sides by z

=> xx <  yx

Dividing both sides by x

=> x < y

True if  x > 0

xxz>yxz

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