Question

(x+y)(u+v)=xu+xv+yu+yv, for any four positive number x,y,u,v using the above identity find 9halfx6 1by3​

Answer 1

Answer:

— ( 10 – 2 ) x 6 = ( 10 x 6 ) ( 2 x 6 ) ( x – y ) ( u – v ) = xu – xv – yu + yv for all positive numbers x , y, u, v with x > y and u > v To find ( x – y )², we put x