x%y when x= -14 and y= -3
Answers
Answered by
1
Explanation:
-14%-3
вut í dσn't knσw hєrє вєcσmє - чα +
4.666%
Answered by
0
Answer:
xy + x'y' + x'y
= xy + x'(y' + y) [distributive law]
= xy + x' [complement law]
= y + x'
The last step is a well-known identity (x' + y = x' + xy), and it can be easily shown as follows:
x' + xy
= ((x' + xy)')' [double negation]
= ((x')'(xy)')' [de Morgan's Theorem]
= (x(x' + y'))' [de Morgan's (again)]
= (xx' + xy')' [distributive]
= (xy')' [complement]
= x' + y [de Morgan's (yet
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