Question

(x-y)whole cube formula​

Answer 1

Step-by-step explanation:

Your Answer -

(x-y)whole cube formula is

x^3 - 3x^2y+3xy^2 - y^3

Answer 2

The expanded formula is x³ - y³ - 3x²y + 3xy².

Given - (x-y)³

Find - Expanded formula

Solution - We can write the given expression as -

$(x - y) \times (x - y) \times (x - y)$

Firstly performing multiplication of first two brackets followed by multiplying the product with last bracket.

Formula = $( {x}^{2} - xy - xy + {y}^{2} ) \times( x - y)$

Formula = $( {x}^{3} - {x}^{2} y - {x}^{2} y + x{y}^{2} - {x}^{2} y + x{y}^{2} + x {y}^{2} - {y}^{3} )$

Formula = ${x}^{3} - {y}^{3} - 3 {x}^{2} y + 3x {y}^{2}$

Hence, the expanded formula is x³ - y³ - 3x²y + 3xy².

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