x y বাস্তব সংখ্যা এবং (x-5)^2+(x-y)^2=0 হলে x ও y এর মান কত
Answers
Answered by
2
Answer:
hi bengali friend.
Step-by-step explanation:
x and y are real numbers...
(x - 5)² + (x - y)² =0
if the added number of two squared forms of things is zero then both things are individually equals to zero... here thing means (x -5) and ( x - y)
so, ( x- 5) =0
x =5 ( x- y) = 0
x = y =5
Similar questions