Question

(x+y)(x-y)+x(x+y)+y(x+y)​

Answer 1

$(x + y)(x - y) + y(x + y) + x(x + y) \\ = > {x}^{2} - {y}^{2} + xy + {y}^{2} + xy + {x}^{2} \\ = > 2 {x}^{2} + 2xy$

Answer 2

Answer:

Before solving the Boolean algebra equation one should be aware with the following simple rules:

A + A = A

A + A' = 1

A. A = A

A. A' = 0

(A+BC)= (A+B)(A+C)

Now comes to the original question , and taking the left part of the equation :

xy + x'y'+x'y ——taking x’ common

= xy+x'(y+y')

= xy+x'. 1 ——-from rule2

= (x + x’)(y+x') ——from rule5

= 1.(x’+y) ———- from rule2

= (x’+y) which is equal to the right term.

Step-by-step explanation:

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