Question

(x+y) ( x+y')( x'+z) = xz

solve boolen expression​

Answer 1

Answer:

Begin with deMorgan's negation

XY+(XZ)′+XY′Z=XY+(X′+Z′)+XY′Z

From there use distribution and complementation until you can't use it any more.

That is: A+A′B=(A+A′)(A+B)=A+B

Explanation:

mark this answer in brainlest answer