Question

(x-y)(x+y)(x²+y²)(x⁴+y⁴
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Answer 1

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Answer 2

$\huge {\underline{\pink{Question:-}}}$

$(x-y)(x+y)(x²+y²)(x⁴+y⁴)$

$\Large\bf\underline\red{Solution:-}$

Step 1:-

Solve $(x-y)(x+y)$

$\longrightarrow$$x(x-y)+y(x-y)$

$\longrightarrow$${x}^2-xy+xy-{y}^2$

$\longrightarrow$${x}^2{y}^2$

So,Now we got the equation

$\longrightarrow$$(x²-y²)(x²+y²)(x⁴+y⁴)$

Step 2:-

Solve $(x²-y²)(x²+y²)$

$\longrightarrow$$x²(x²-y²)+y²(x²-y²)$

$\longrightarrow$$x⁴-x²y²+x²y²-y⁴$

$\longrightarrow$$x⁴-y⁴$

So,Now we got the equation

$\longrightarrow$$(x⁴-y⁴)(x⁴+y⁴)$

$\longrightarrow$$x⁴(x⁴-y⁴)+y⁴(x⁴-y⁴)$

$\longrightarrow$${x}^8-x⁴y⁴+x⁴y⁴-{y}^8$

$\longrightarrow$${x}^8-{y}^8$

So,The value of the equation:-$(x-y)(x+y)(x²+y²)(x⁴+y⁴)$$\longrightarrow$${x}^8-{y}^8$

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