Math, asked by sakshamdeshmukh74, 2 months ago

(x + y)(x - y) + (y + z)(y - z) + (x + z)(x - z) = 0​

Answers

Answered by Princeroy61
1

(x + y)(x - y) + (y + z)(y - z) + (x + z)(x - z

for this question point is very less so sorry I can't help you.

Answered by karishmarahi
0

Step-by-step explanation:

X(x-y) + y(x-y) + y(y-z)+z(y-z) + X(x-z)+z(x-z) = 0

 {x}^{2}  - xy + yx -  {y}^{2}  +  {y}^{2}   - yz+ zy -  {z}^{2}  -  {x}^{2}  - xz + zx  +   {z}^{2}   \\  \\

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