Question

(x+y)(x-y) +(y+z)(y-z) +(z+x)(z-x) =0​

Answer 1

Answer:

This is the Solution of your question and explaination with step by step.

Answer 2

(x+y)(x-y) +(y+z)(y-z) +(z+x)(z-x) =0

x(x-y)+y(x-y) + y(y-z)+z (y-z) + z(z-x) + x(z-x)

(x² - xy + yx - xy - y²) + (y² - yz + zy - z²) + ( z² - zx + xz - x² )

x² - xy + yx - xy - y² + y² - yz + zy - z² + z² - zx + xz - x²

LHS = RHS

0 = 0