(x-y)(x+y)(y-z)(y+z)(z-x)(z-x)
Answers
Answered by
1
Answer:
0
Step-by-step explanation:
(x-y)(x+y)=0
(y-z)(y+z)=0
(z-x)(z+x)=0
therefore :-(x-y)(x+y)(y-z)(y+z)(z-x)(z+x)=0
I hope this answer would be helpful for you.
Similar questions