Math, asked by minakhi25041980, 6 months ago

(x-y) (x+y)+(y-z)(y+z) +(z-x) (z+x)​

Answers

Answered by amithalwai77
0
x^2-y^2+y^2-z^2+z^2-x^2=0
Answered by singhdisha687
1

Answer:

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Step-by-step explanation:

Given that,

xy(x−y)+yz(y−z)+zx(z−x)

=xxy−xyy+y

2

z−yz

2

+xz

2

−x

2

z

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