Math, asked by manjusudarshanreddy, 6 months ago

(x-y)(x+y)+(y-z)(y+z)+(z-x)(z+x)​

Answers

Answered by Anonymous
1

Answer:

The term (x+y)(x-y)+(y+z)(y-z)+(z+x)(z-x) = 0

Answered by sriyasalonirout
0

Answer:

0 is the answer..

Step-by-step explanation:

(x-y)(x+y)+(y-z)(y+z)+(z-x)(z+x)

=x²+xy-xy-y²+y²+yz-yz-z²+z²+zx-zx-x²

=0

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