(x-y)(x+y)+(y-z)(y+z)+(z-x)(z+x)
Answers
Answered by
1
Answer:
The term (x+y)(x-y)+(y+z)(y-z)+(z+x)(z-x) = 0
Answered by
0
Answer:
0 is the answer..
Step-by-step explanation:
(x-y)(x+y)+(y-z)(y+z)+(z-x)(z+x)
=x²+xy-xy-y²+y²+yz-yz-z²+z²+zx-zx-x²
=0
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