(x-y)(x+y)+(y-z)(y+z)+(z-x)(z+x) =
Answers
Answered by
2
Answer:
O is the answer of this question
Step-by-step explanation:
(x-y)(x+y)+(y-z)(y+z)+(z-x)(z+x)
(x^2-y^2)+(y^2-z^2)+(z^2-x^2)
= 0
Similar questions