Math, asked by juiparab2608, 3 months ago

(x-y)(x+y)+(y-z)(y+z)+(z-x)(z+x) =

Answers

Answered by jitendraparori
2

Answer:

O is the answer of this question

Step-by-step explanation:

(x-y)(x+y)+(y-z)(y+z)+(z-x)(z+x)

(x^2-y^2)+(y^2-z^2)+(z^2-x^2)

= 0

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