Question

(x-y) (x-y) + (y-z) (y+z) + (z-x) (z+x) is equal to ___________
a) 0
b) x²+y²
c) xy+ yz + zx


Any one told right answer I will mark them as brainliest ​

Answer 1

Answer:

Answer:

x(y-z)+y(z-x)+z(x-y)

=xy-xz+yz-yx+zx-zy

=0

Step-by-step explanation:

hey mate! here u go （＾ｖ＾）

=x(y-z)+y(z-x)+z(x-y)

=xy-xz+yz-xy+xz-yz

=(xy-xy)+(-xz+xz)+(yz-yz)

=(0)+(0)+(0)

=0

Step-by-step explanation:

HENCE, ANS IS 0