Math, asked by Anonymous, 4 months ago

x – y)(x + y) + (y – z)(y + z) + (z – x) (z + x) is equal to

Can anyone say the answer of this question

Answers

Answered by IIJustAWeebII
3

 \mathfrak{ \large{ \boxed{✿Answer \: is \: 0}}}

 \sf{ \purple{Formula \: used :-}}

 \mathcal{ \blue{ \boxed{ \boxed{(a - b)(a + b) = a {}^{2}  - b {}^{2} }}}}

 \sf{(x – y)(x + y) + (y – z)(y + z) + (z – x) (z + x)}

 \sf{ =  > x {}^{2}  -  {y}^{2}  +  {y}^{2}  - z {}^{2}  +  {z}^{2}  - x {}^{2}}

 \sf{ =  > 0}

 \mathfrak{ \green{✤Hope \: this \: helps! }}

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