Question

(x+y)(x+y)-z(x+y)=a(x+y-z) then a=

Answer 1

Answer:

a=x+y

Step-by-step explanation:

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Answer 2

Answer:a=x+y

Step-by-step explanation: taking LHS

(x+y)(x+y)-z(x+y)

(x+y)^2-z(x+y)

Taking x+y common

(x+y)(x+y-z)=a(x+y-z)

x+y-z gets cancelled

So, a=x+y