x*y =√x²+y²,find the value of( 1*2√2)(1*-2√2 )
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x* y =√x²+y²
[1*2√2][1* -2√2]
=[√1²+(2√2)²][√1²+(-2√2)²
=[√1+8][√1+8]
=(√9)(√9)
=√9x9
=+ or - 9
[1*2√2][1* -2√2]
=[√1²+(2√2)²][√1²+(-2√2)²
=[√1+8][√1+8]
=(√9)(√9)
=√9x9
=+ or - 9
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