Math, asked by mittalray12, 9 months ago

x+y/xy=2 x-y/xy=6 find the values of x and y​

Answers

Answered by archanajoshi2711
1

Answer:

x=-1/2

y=1/4

Step-by-step explanation:

 \frac{x + y}{xy}  = 2 \\  \frac{x - y}{xy}  = 6

 \frac{x + y}{xy}  +  \frac{x - y}{xy}  = 2 + 6 \\  \frac{x + y + x - y}{xy}  = 8

 \frac{2x}{xy}  = 8 \\ 2x =  8xy

  \frac{1}{y}  =  \frac{8x}{2x }  \\  \frac{1}{y}  = 4

y =  \frac{1}{4}

   \frac{x +  \frac{1}{4} }{x \frac{1}{4} }  = 2 \\ x +  \frac{1}{4}  \times  \frac{4}{x}  = 2

 \frac{4x + 1}{4}  \times  \frac{4}{x}  = 2

4x + 1 = 2 \times  \frac{x}{4}  \times 4 \\ 4x  + 1= 2x

4x - 2x =  - 1 \\ 2x =  - 1

x =  \frac{ - 1}{2}

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