x + y + xy = 29 Y+z+Yz = 41
z+x+xz= 34 then find 3z-4x+5y = ?
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3×6-4×4+5×5= 27?????
I think I'm right coz' after thinking a lot I found the values which completely fits to all the 3 conditions given by you ...
as x=4 , y=5 and z=6
so, in the first case, 5+4+5×4=9+20=29
in the second case, 5+6+5×6= 11+30=41
in the 3rd case = 6+4+6×4=10+24=34
therefore.....
x=4, y=5 and z=6
therefore my answer is correct dear....
may you have a great life...
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