Question

x/y + y/x =1 find x^3+y^3

Answer 1

Step-by-step explanation:

x/y + y/x = 1

x² + y² = xy

x² + y² - xy = 0

x² - xy + y² = 0

x³ + y³ = (x+y){x² - xy + y²}

= (x+y) * 0 = 0

Answer 2

(x/y)+(y/x)=1

=> (x^2 + y^2)/xy = 1

=> (x^2 + y^2) =xy

=>(x^2 + y^2 -xy) =0 —————(1)

As we know, x^3 + y^3 = (x+y)*(x^2 - xy+y^2)

So x^3+y^3 =0 ( since from equation 1 we have x^2-xy+y^2=0)

HOPE IT HELPS YOU

PLEASE MARK AS BRAINLIEST